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Comments re Chapter 14 Problems:

14-7	An exercise in converting charge per mole of ions to charge in Coulombs.
14-12	Another T/F exercise.
14-13	Exercise in working out the number of electrons transferred in a redox reaction or in a half-reaction.
14-14	Use of DfG^o data to calculate DrxnG^o, which is then converted to an E^o value. An important point of this problem is the relationship between the magnitudes of the DrxnG^o and E^o values. An E^o value of 0.5 V corresponds to a large (negative) value of DrxnG^o. Note that DfG^o values for ions are needed to calculate DrxnG^o. There are entries for the necessary ions in Levine's table of thermodynamic properties.
14-15	A small thought problem involving E, E^o, ionic strength, and activity coefficients.
14-20	Another small thought problem.
14-27	An exercise based on the relationship E = E^o - (RT/nF)l lnQ, which is the Nernst equation. The E^o value for the cell is 0.2222 V.
14-28	A straightforward problem in which E is to be calculated given the cell and the ion activities. The only complication is that E for the cell is negative, which means that the anode on the left is really the cathode if the cell is run as a battery. That switch reverses the direction of electron flow. In answering the question remember that electrons flow from regions of lower electrical potential to higher electrical potential because the sign of the charge on the electron was chosen to be negative.
14-29	Another problem based on the Nernst equation, but this time it is the activity coefficients that are included.
14-31	An exercise in adding two half-cell E^o values together to get an E^o value for a third half-reaction. The the answer obtained by simply summing the two E^o values for the two half-reactions given is wrong.
14-32	Estimation of the voltage for a simple cell from E^o values and from activity coefficients estimated using the Davies equation.
14-37	A short T/F question.
14-39	Calculation of an interesting equilibrium constant from E^o values.
14-40	Exercise that demonstrates how DfG^o values can be determined for ions. Remember that E^o for the reduction of H^+(aq), and DfG^o and DfH^o for H^+(aq) are all zero.
14-41	Problem in which the Ksp for PbI2 is determined from E^o values.

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